Английская Википедия:Baer–Specker group

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Версия от 09:33, 5 февраля 2024; EducationBot (обсуждение | вклад) (Новая страница: «{{Английская Википедия/Панель перехода}} {{Short description|Infinite Abelian group}} In mathematics, in the field of group theory, the '''Baer–Specker group''', or '''Specker group''', named after Reinhold Baer and Ernst Specker, is an example of an infinite Abelian group which is a building block in the structure theory of such groups. ==Definition== The Baer–Specker group is the group ''B'' = '''Z'...»)
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Шаблон:Short description In mathematics, in the field of group theory, the Baer–Specker group, or Specker group, named after Reinhold Baer and Ernst Specker, is an example of an infinite Abelian group which is a building block in the structure theory of such groups.

Definition

The Baer–Specker group is the group B = ZN of all integer sequences with componentwise addition, that is, the direct product of countably many copies of Z. It can equivalently be described as the additive group of formal power series with integer coefficients.

Properties

Reinhold Baer proved in 1937 that this group is not free abelian; Specker proved in 1950 that every countable subgroup of B is free abelian.

The group of homomorphisms from the Baer–Specker group to a free abelian group of finite rank is a free abelian group of countable rank. This provides another proof that the group is not free.[1]

See also

Notes

Шаблон:Reflist

References

External links

  1. Шаблон:Harvtxt attribute this result to Шаблон:Harvtxt. They write it in the form <math>P^*\cong S</math> where <math>P</math> denotes the Baer-Specker group, the star operator gives the dual group of homomorphisms to <math>\mathbb{Z}</math>, and <math>S</math> is the free abelian group of countable rank. They continue, "It follows that <math>P</math> has no direct summand isomorphic to <math>S</math>", from which an immediate consequence is that <math>P</math> is not free abelian.