Английская Википедия:Hooke's atom

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Шаблон:Short description Hooke's atom, also known as harmonium or hookium, refers to an artificial helium-like atom where the Coulombic electron-nucleus interaction potential is replaced by a harmonic potential.[1][2] This system is of significance as it is, for certain values of the force constant defining the harmonic containment, an exactly solvable[3] ground-state many-electron problem that explicitly includes electron correlation. As such it can provide insight into quantum correlation (albeit in the presence of a non-physical nuclear potential) and can act as a test system for judging the accuracy of approximate quantum chemical methods for solving the Schrödinger equation.[4][5] The name "Hooke's atom" arises because the harmonic potential used to describe the electron-nucleus interaction is a consequence of Hooke's law.

Definition

Employing atomic units, the Hamiltonian defining the Hooke's atom is

<math>\hat{H} = -\frac{1}{2}\nabla^{2}_{1} -\frac{1}{2}\nabla^{2}_{2} + \frac{1}{2}k(r^{2}_{1}+r^{2}_{2}) + \frac{1}{|\mathbf{r}_{1}-\mathbf{r}_{2}|}.</math>

As written, the first two terms are the kinetic energy operators of the two electrons, the third term is the harmonic electron-nucleus potential, and the final term the electron-electron interaction potential. The non-relativistic Hamiltonian of the helium atom differs only in the replacement:

<math>-\frac{2}{r} \rightarrow \frac{1}{2}kr^{2}.</math>

Solution

The equation to be solved is the two electron Schrödinger equation:

<math>\hat{H}\Psi(\mathbf{r}_{1},\mathbf{r}_{2}) = E\Psi(\mathbf{r}_{1},\mathbf{r}_{2}).</math>

For arbitrary values of the force constant, Шаблон:Math, the Schrödinger equation does not have an analytic solution. However, for a countably infinite number of values, such as Шаблон:Math, simple closed form solutions can be derived.[5] Given the artificial nature of the system this restriction does not hinder the usefulness of the solution.

To solve, the system is first transformed from the Cartesian electronic coordinates, Шаблон:Math, to the center of mass coordinates, Шаблон:Math, defined as

<math>\mathbf{R}=\frac{1}{2}(\mathbf{r}_{1}+\mathbf{r}_{2}), \mathbf{u}=\mathbf{r}_{2}-\mathbf{r}_{1}.</math>

Under this transformation, the Hamiltonian becomes separable – that is, the Шаблон:Math term coupling the two electrons is removed (and not replaced by some other form) allowing the general separation of variables technique to be applied to further a solution for the wave function in the form <math>\Psi(\mathbf{r}_{1},\mathbf{r}_{2})=\chi(\mathbf{R})\Phi(\mathbf{u})</math>. The original Schrödinger equation is then replaced by:

<math>\left( -\frac{1}{4}\nabla^{2}_{\mathbf{R}}+kR^{2} \right)\chi(\mathbf{R}) = E_{\mathbf{R}}\chi(\mathbf{R}),</math>
<math>\left( -\nabla^{2}_{\mathbf{u}}+\frac{1}{4}ku^{2} +\frac{1}{u}\right)\Phi(\mathbf{u}) = E_{\mathbf{u}}\Phi(\mathbf{u}).</math>

The first equation for <math>\chi(\mathbf{R})</math> is the Schrödinger equation for an isotropic quantum harmonic oscillator with ground-state energy <math>E_{\mathbf{R}}=(3/2)\sqrt{k} E_{\mathrm{h}}</math> and (unnormalized) wave function

<math>\chi(\mathbf{R}) = e^{-\sqrt{k}R^{2}}.</math>

Asymptotically, the second equation again behaves as a harmonic oscillator of the form <math>\exp(-(\sqrt{k}/4)u^{2})\,</math> and the rotationally invariant ground state can be expressed, in general, as <math>\Phi(\mathbf{u})=f(u)\exp(-(\sqrt{k}/4)u^{2})\,</math> for some function <math>f(u)\,</math>. It was long noted that Шаблон:Math is very well approximated by a linear function in Шаблон:Math.[2] Thirty years after the proposal of the model an exact solution was discovered for Шаблон:Math,[3] and it was seen that Шаблон:Math. It was later shown that there are many values of Шаблон:Math which lead to an exact solution for the ground state,[5] as will be shown in the following.

Decomposing <math>\Phi(\mathbf{u})=R_{l}(u)Y_{lm}</math> and expressing the Laplacian in spherical coordinates,

<math>\left( -\frac{1}{u^{2}}\frac{\partial}{\partial u}\left(u^{2}\frac{\partial}{\partial u}\right) + \frac{\hat{L}^{2}}{u^{2}} +\frac{1}{4}ku^{2} +\frac{1}{u}\right)R_{l}(u)Y_{lm}(\hat{\mathbf{u}}) = E_{l}R_{l}(u)Y_{lm}(\hat{\mathbf{u}}),</math>

one further decomposes the radial wave function as <math>R_{l}(u)=S_{l}(u)/u\,</math> which removes the first derivative to yield

<math>-\frac{\partial^{2}S_{l}(u)}{\partial u^{2}}+\left(\frac{l(l+1)}{u^{2}}+\frac{1}{4}ku^{2}+\frac{1}{u}\right)S_{l}(u) = E_{l}S_{l}(u).</math>

The asymptotic behavior <math>S_{l}(u) \sim e^{-\frac{\sqrt{k}}{4}u^{2}}\,</math> encourages a solution of the form

<math>S_{l}(u) = e^{-\frac{\sqrt{k}}{4}u^{2}}T_{l}(u).</math>

The differential equation satisfied by <math>T_{l}(u)\,</math> is

<math>-\frac{\partial^{2}T_{l}(u)}{\partial u^{2}} + \sqrt{k}u\frac{\partial T_{l}(u)}{\partial u} + \left(\frac{l(l+1)}{u^{2}}+\frac{1}{u}+\left(\frac{\sqrt{k}}{2}-E_{l}\right)\right)T_{l}(u) = 0.</math>

This equation lends itself to a solution by way of the Frobenius method. That is, <math>T_{l}(u)\,</math> is expressed as

<math>T_{l}(u) = u^{m}\sum_{k=0}^{\infty}\ a_{k}u^{k}.</math>

for some <math>m\,</math> and <math>\{a_{k}\}_{k=0}^{k=\infty}\,</math> which satisfy:

<math>m(m-1) = l(l+1)\,, </math>
<math>a_{0} \neq 0\, </math>
<math>a_{1} = \frac{a_{0}}{2(l+1)}, </math>
<math>a_{2} = \frac{a_{1} + \left(\sqrt{k}(l+\frac{3}{2})-E_{l}\right)a_{0}}{2(2l+3)} = \frac{a_{0}}{2(2l+3)}\left(\frac{1}{2(l+1)}+\sqrt{k}\left(l+\frac{3}{2}\right)-E_{l}\right),</math>
<math>a_{3} = \frac{a_{2} + \left(\sqrt{k}(l+\frac{5}{2})-E_{l}\right)a_{1}}{6(l+2)},</math>
<math>a_{n+1} = \frac{a_{n} + \left(\sqrt{k}(l+\frac{1}{2}+n)-E_{l}\right)a_{n-1}}{(n+1)(2l+2+n)}. </math>

The two solutions to the indicial equation are <math>m = l+1</math> and <math>m = -l</math> of which the former is taken as it yields the regular (bounded, normalizable) wave function. For a simple solution to exist, the infinite series is sought to terminate and it is here where particular values of Шаблон:Math are exploited for an exact closed-form solution. Terminating the polynomial at any particular order can be accomplished with different values of Шаблон:Math defining the Hamiltonian. As such there exists an infinite number of systems, differing only in the strength of the harmonic containment, with exact ground-state solutions. Most simply, to impose Шаблон:Math for Шаблон:Math, two conditions must be satisfied:

<math>\frac{1}{2(l+1)}+\sqrt{k}\left(l+\frac{3}{2}\right)-E_{l} = 0,</math>
<math>\sqrt{k}(l+\frac{5}{2})=E_{l}.</math>

These directly force Шаблон:Math and Шаблон:Math respectively, and as a consequence of the three term recession, all higher coefficients also vanish. Solving for <math>\sqrt{k}\,</math> and <math>E_{l}\,</math> yields

<math>\sqrt{k} = \frac{1}{2(l+1)},</math>
<math>E_{l} = \frac{2l+5}{4(l+1)},</math>

and the radial wave function

<math>T_{l} = u^{l+1}\left(a_{0}+\frac{a_{0}}{2(l+1)}u\right).</math>

Transforming back to <math>R_{l}(u)\,</math>

<math>R_{l}(u) = \frac{T_{l}(u)e^{-\frac{\sqrt{k}}{4}u^{2}}}{u} = u^{l}\left(1+\frac{1}{2(l+1)}u\right)e^{-\frac{\sqrt{k}}{4}u^{2}},</math>

the ground-state (with <math>l=0\,</math> and energy <math>5/4 E_{\mathrm{h}}\,</math>) is finally

<math>\Phi(\mathbf{u}) = \left(1+\frac{u}{2}\right)e^{-u^{2}/8}.</math>

Combining, normalizing, and transforming back to the original coordinates yields the ground state wave function:

<math>\Psi(\mathbf{r}_{1},\mathbf{r}_{2}) = \frac{1}{2\sqrt{8\pi^{5/2}+5\pi^{3}}}\left(1+\frac{1}{2}|\mathbf{r}_{1}-\mathbf{r}_{2}|\right)\exp\left(-\frac{1}{4}\big(r_{1}^{2}+r_{2}^{2}\big)\right).</math>

The corresponding ground-state total energy is then <math>E=E_R+E_u=\frac{3}{4}+\frac{5}{4} = 2 E_{\mathrm{h}}</math>.

Remarks

The exact ground state electronic density of the Hooke atom for the special case <math>k=1/4</math> is[4]

<math>\rho(\mathbf{r}) = \frac{2}{\pi^{3/2}(8+5\sqrt{\pi})}e^{-(1/2)r^{2}}\left(\left(\frac{\pi}{2}\right)^{1/2}\left(\frac{7}{4}+\frac{1}{4}r^{2}+\left(r+\frac{1}{r}\right)\mathrm{erf}\left(\frac{r}{\sqrt{2}}\right)\right)+e^{-(1/2)r^{2}}\right).</math>

From this we see that the radial derivative of the density vanishes at the nucleus. This is in stark contrast to the real (non-relativistic) helium atom where the density displays a cusp at the nucleus as a result of the unbounded Coulomb potential.

See also

References

Шаблон:Reflist

Further reading